How to linearize your cluster

In this case the weights are 100-50=50 for A, 3980-2500=1480 for B, and 920-2450=-1530 for C. So the min-cut will pick AB as first subset/chunk.

Next you can choose to see if optimizing AB further is even better: the new \lambda is the new breakpoint is the combined feerate of AB, which is 4080/51=80. Then the new weights become 20 for A, -20 for B, -3000 for C. So the min-cut will pick A as the next best chunk. We could let the algorithm run again with the new breakpoint \lambda=100 and see that now we get the empty set or maybe A again, but we already know that a single node cannot be improved upon, so the optimal chunking is (A,B,C).

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